{"version":"1.0","provider_name":"Grak\u0161tuol\u0117 Straipsniai","provider_url":"https:\/\/www.grakstuole.lt\/straipsniai","author_name":"Marius","author_url":"https:\/\/www.grakstuole.lt\/straipsniai\/author\/marius\/","title":"Lazerinis plauk\u0173 \u0161alinimas prie\u0161 ir po: ko tik\u0117tis po keli\u0173 proced\u016br\u0173 - Grak\u0161tuol\u0117 Straipsniai","type":"rich","width":600,"height":338,"html":"<blockquote class=\"wp-embedded-content\"><a href=\"https:\/\/www.grakstuole.lt\/straipsniai\/ko-tiketis-po-keliu-proceduru\/\">Lazerinis plauk\u0173 \u0161alinimas prie\u0161 ir po: ko tik\u0117tis po keli\u0173 proced\u016br\u0173<\/a><\/blockquote>\n<script type='text\/javascript'>\n<!--\/\/--><![CDATA[\/\/><!--\n\t\t\/*! This file is auto-generated *\/\n\t\t!function(d,l){\"use strict\";var e=!1,n=!1;if(l.querySelector)if(d.addEventListener)e=!0;if(d.wp=d.wp||{},!d.wp.receiveEmbedMessage)if(d.wp.receiveEmbedMessage=function(e){var t=e.data;if(t)if(t.secret||t.message||t.value)if(!\/[^a-zA-Z0-9]\/.test(t.secret)){for(var r,i,a,s=l.querySelectorAll('iframe[data-secret=\"'+t.secret+'\"]'),n=l.querySelectorAll('blockquote[data-secret=\"'+t.secret+'\"]'),o=new RegExp(\"^https?:$\",\"i\"),c=0;c<n.length;c++)n[c].style.display=\"none\";for(c=0;c<s.length;c++)if(r=s[c],e.source===r.contentWindow){if(r.removeAttribute(\"style\"),\"height\"===t.message){if(1e3<(a=parseInt(t.value,10)))a=1e3;else if(~~a<200)a=200;r.height=a}if(\"link\"===t.message)if(i=l.createElement(\"a\"),a=l.createElement(\"a\"),i.href=r.getAttribute(\"src\"),a.href=t.value,o.test(a.protocol))if(a.host===i.host)if(l.activeElement===r)d.top.location.href=t.value}}},e)d.addEventListener(\"message\",d.wp.receiveEmbedMessage,!1),l.addEventListener(\"DOMContentLoaded\",t,!1),d.addEventListener(\"load\",t,!1);function t(){if(!n){n=!0;for(var e,t,r=-1!==navigator.appVersion.indexOf(\"MSIE 10\"),i=!!navigator.userAgent.match(\/Trident.*rv:11\\.\/),a=l.querySelectorAll(\"iframe.wp-embedded-content\"),s=0;s<a.length;s++){if(!(e=a[s]).getAttribute(\"data-secret\"))t=Math.random().toString(36).substr(2,10),e.src+=\"#?secret=\"+t,e.setAttribute(\"data-secret\",t);if(r||i)(t=e.cloneNode(!0)).removeAttribute(\"security\"),e.parentNode.replaceChild(t,e)}}}}(window,document);\n\/\/--><!]]>\n<\/script><iframe sandbox=\"allow-scripts\" security=\"restricted\" src=\"https:\/\/www.grakstuole.lt\/straipsniai\/ko-tiketis-po-keliu-proceduru\/embed\/\" width=\"600\" height=\"338\" title=\"\u201eLazerinis plauk\u0173 \u0161alinimas prie\u0161 ir po: ko tik\u0117tis po keli\u0173 proced\u016br\u0173\u201c &#8212; Grak\u0161tuol\u0117 Straipsniai\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" class=\"wp-embedded-content\"><\/iframe>","thumbnail_url":"https:\/\/www.grakstuole.lt\/straipsniai\/wp-content\/uploads\/2025\/12\/Screenshot_2.jpg","thumbnail_width":669,"thumbnail_height":542,"description":"&nbsp; Po pirmos lazerinio plauk\u0173 \u0161alinimo proced\u016bros plaukeliai pradeda kristi ma\u017edaug po 14 dien\u0173 ir toje vietoje i\u0161 prad\u017ei\u0173 nebeauga nauji. Ta\u010diau pilnam rezultatui pasiekti rekomenduojamas 8\u201310 proced\u016br\u0173 kursas, nes vienu metu aktyvioje augimo faz\u0117je yra tik dalis k\u016bno plaukeli\u0173. Geriausius rezultatus pastebi \u0161viesios odos ir tamsi\u0173 plauk\u0173 savininkai; po viso kurso plaukuotumas \u017eenkliai suma\u017e\u0117ja, &hellip;"}